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Home/ Questions/Q 8171311
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T21:25:25+00:00 2026-06-06T21:25:25+00:00

i first create a Json String with String myJsonString = new Gson().toJson(myElement); this works

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i first create a Json String with

String myJsonString = new Gson().toJson(myElement);

this works fine.
After that, i want to add this String to anothe big jsonObject to send it to backend with other vars.

jsonObject.put("Tests",myJsonString);

but with this line of code the special character will be escaped and the parser on the backend didnt get it.
How can I avoid it, that myJsonString will be serialized again?

jsonObject.put("Tests",myElement);

doesnt work, because after that there are only references in the jsonObject but no values.

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  1. Editorial Team
    Editorial Team
    2026-06-06T21:25:26+00:00Added an answer on June 6, 2026 at 9:25 pm
    jsonObject.put("Tests", new JSONObject(myJsonString));
    

    (assuming jsonObject is of type org.json.JSONObject)

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