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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:00:32+00:00 2026-05-16T07:00:32+00:00

I first create my grid: grid = [] for x in range(1,collength + 1):

  • 0

I first create my grid:

grid = []
for x in range(1,collength + 1):
    for y in range(1,collength + 1):
        grid.append([x,y,'e'])

Then I make que for my grid and I want to manipulate the que based on the 0, 1, and 2 position of the lists inside the lists:

floodfillque = []

grid = floodfillque

for each in floodfillque:
    floodfilllist = []
    currentfloodfill = []
    print '::'
    print each[1]

But when I try to print each[1] I get the whole list, not just the nth element of the list inside the list

What am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:00:33+00:00Added an answer on May 16, 2026 at 7:00 am

    As you have written it, your code iterates over an empty list. I think you mean:

    for each in grid:
    

    or perhaps:

    floodfillque = grid
    

    This code works fine:

    collength = 3
    
    grid = []
    for x in range(1,collength + 1):
        for y in range(1,collength + 1):
            grid.append([x,y,'e'])
    
    for each in grid:
        floodfilllist = []
        currentfloodfill = []
        print '::'
        print each[1]
    

    Result:

    ::
    1
    ::
    2
    ::
    3
    ::
    1
    ::
    2
    ::
    3
    ::
    1
    ::
    2
    ::
    3
    
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