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Asked: 2026-05-20T10:09:53+00:00

I found out that I have two versions of ruby installed on OSX 10.6.2

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I found out that I have two versions of ruby installed on OSX 10.6.2 how can I uninstall the older version and make sure that everything is fine, the path point to the other one? 

bash-3.2$  /usr/local/bin/ruby -v 
ruby 1.8.7 (2009-06-12 patchlevel 174) [i686-darwin9.7.0]

bash-3.2$ /usr/bin/ruby -v
ruby 1.8.7 (2008-08-11 patchlevel 72) [universal-darwin10.0]


bash-3.2$ $PATH
bash: /usr/local/bin:/bin:/sbin:/usr/bin:/usr/sbin:/usr/libexec: No such file or directory

bash-3.2$ whereis ruby
/usr/bin/ruby
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  1. Editorial Team

    The version of Ruby in /usr/bin is the system-installed version, and should be left in place.

    The version you have in /usr/local/bin can probably be safely removed. Was it installed using a package manager (ie, MacPorts, Homebrew?). If so, remove it using your package manager.

    If you compiled and installed it manually, you can try removing the binaries from /usr/local/bin, but you may still have gems and other files lying around (most likely in /usr/local/lib/ruby.)

    Alternatively, you can leave them in place and manage your Ruby environment through RVM: http://rvm.beginrescueend.com/

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