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Home/ Questions/Q 8523049
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T07:17:58+00:00 2026-06-11T07:17:58+00:00

I found that the constant literal is computed at compile time for example: int

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I found that the constant literal is computed at compile time for example:int a=10+20; but when i try to use int b=10/0; i find that it is computed at run time.
Can you please tell me why this constant literal is computed at run time?
Thank you.

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  1. Editorial Team
    Editorial Team
    2026-06-11T07:18:00+00:00Added an answer on June 11, 2026 at 7:18 am

    A constant value MAY be computed at compile time, if the compiler can maintain the same semantics as if it were done at run time. If not (eg, the case of divide by zero) then it defers the computation to run time. For more info read JLS 15.28.

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