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Editorial Team
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Asked: 2026-06-12T03:29:21+00:00

I found the following weird behavior while working on JavaScript numbers. var baseNum =

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I found the following weird behavior while working on JavaScript numbers.

var baseNum = Math.pow(2, 53);
console.log(baseNum); //prints 9007199254740992

console.log(baseNum + 1); //prints 9007199254740992 again!

console.log(baseNum + 2); //prints 9007199254740994, 2 more than +1

console.log(baseNum + 3) // prints 9007199254740996, 2 more than +2
console.log(baseNum + 4) // prints 9007199254740996, same as +3

What is happening here? I understand that JavaScript can only represent numbers upto 2^53 (they are internally ‘double’?), but why this behavior?

If 2^53 is the practical max, then why do we have Number.MAX_VALUE (1.7976931348623157e+308)?.

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1 Answer

  1. Editorial Team

    The number is really a double. The mantissa has 52-bits (source and extra information on doubles). Therefore, storing 2^53 chops off the one bit.

    The number is stored using 3 pieces a sign bit (fairly straight forward) and two other pieces, the mantissa M and the exponent E. The number is calculated as:

    (1 + M/2^53) * 2^(E-1023)

    I might have some of the specifics there a little off, but the basic idea is there. So when the number is 2^53, 2^(E-1023) = 2^53 and since there are only 52 bits in M, you can no longer represent the lowest bit.

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