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Editorial Team
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Asked: 2026-06-13T13:30:30+00:00

I found this code below and it works perfect for what I want BUT

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I found this code below and it works perfect for what I want BUT I have over 30 options is there something else I can do to shorten the code?

<html>
<body>
    <form method="post" action="?">
    <select name="dropdown">
    <option value="Jehzeel1">Jehzeel1</option>
    <option value="Jehzeel2">Jehzeel2</option>
    <option value="Jehzeel3">Jehzeel3</option>
    </select>
    <input type="submit" value="submit">
    </form>
</body>
</html>



    <?php
    switch ($_POST['dropdown'])  { 

        case "Jehzeel1":
         echo "Jehzeel likes apples";
        break;

        case "Jehzeel2":
         echo "Jehzeel likes bananas";
        break;

        case "Jehzeel3":
         echo "Jehzeel likes oranges";
        break;

    ?>
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1 Answer

  1. Editorial Team

    It’s easier to create a mapping array:

    $map = array(
    'Jehzeel2' => 'Jehzeel likes bananas';
    'Jehzeel3' => 'Jehzeel likes oranges';
);

echo $map[$_POST['dropdown']];

    Although you may want to think twice about your code structure, this looks like a bad practice.

    Short way:

    <?php
$fruits = array('apples', 'oranges', 'bananas');
?>
<form method="post">
    <select name="dropdown">
    <?php foreach ($fruits as $fruit) : ?>
        <option value="<?php echo $fruit ?>"><?php echo $fruit ?></option>
    <?php endforeach; ?>
    </select>
    <input type="submit" value="submit" />
</form>
<?php
if (in_array($_POST['dropdown'], $fruits)) {
    echo 'Jehzeel likes ' . $_POST['dropdown'];
}
?>

    EDIT

    You can use urls by slightly changing the array and the if statement:

    $urls = array('url1' => 'http://www.facebook.com/', 'url2' => 'http://www.google.com/', 'url3' => 'http://www.yahoo.com/');

if (isset($urls[$_POST['dropdown']])) {
    echo 'URL: ' . $urls[$_POST['dropdown']];
}
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