Question

I found this code for converting text-to-image and I wanted to echo the result

<?php
// Set the content-type
header('Content-type: image/png');

// Create the image
$im = imagecreatetruecolor(400, 30);

// Create some colors
$white = imagecolorallocate($im, 255, 255, 255);
$grey = imagecolorallocate($im, 128, 128, 128);
$black = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 0, 0, 399, 29, $white);

// The text to draw
$text = 'Testing...';
// Replace path by your own font path
$font = 'arial.ttf';

// Add some shadow to the text
imagettftext($im, 20, 0, 11, 21, $grey, $font, $text);

// Add the text
imagettftext($im, 20, 0, 10, 20, $black, $font, $text);

// Using imagepng() results in clearer text compared with imagejpeg()
imagepng($im);
imagedestroy($im);
?> 

for example I saved that code to image.php, I can echo that image by

echo"<img src='image.php'>";

but I don’t want to do that way, because if I did, I cant assign variable text.

Is there any other way to print the image from that code?

Answer 1

in your image.php

replace

 $text = 'Testing...';

with

 $text=$_GET["text"];

and your code to print

echo"<img src='image.php?text=AnotherText...'>";

Hope this is what you want?

EDIT:

<form action="image.php" method="post">
<textarea name="text"></textarea>
<input type="Submit" value="Submit">
</form>

in your image.php file instead of

$text=$_GET["text"];

use

$text=$_POST["text"];