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Home/ Questions/Q 724097
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:10:59+00:00 2026-05-14T06:10:59+00:00

I found this code here class Usable; class Usable_lock { friend class Usable; private:

  • 0

I found this code here

class Usable;

class Usable_lock {
    friend class Usable;
private:
    Usable_lock() {}
    Usable_lock(const Usable_lock&) {}
};

class Usable : public virtual Usable_lock {
    // ...
public:
    Usable();
    Usable(char*);
    // ...
};

Usable a;

class DD : public Usable { };

DD dd;  // error: DD::DD() cannot access
        // Usable_lock::Usable_lock(): private  member

Could anybody explain me this code?

EDIT: Also another question i have is what is a virtual derivation and when is it needed?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:11:00+00:00Added an answer on May 14, 2026 at 6:11 am

    It’s a property of virtual derivation.

    The idea of virtual derivation is to solve the “Dreaded Diamond Pattern”:

    struct Base {};
    
    struct D1: Base {};
    struct D2: Base {};
    
    struct TopDiamond: D1, D2 {};
    

    The problem here is that TopDiamond has 2 instance of Base here.

    To solve this problem, very peculiar “MultiInheritance”, C++ uses the virtual keyword and what is thus called “virtual inheritance”.

    If we change the way D1 and D2 are defined such that:

    struct D1: virtual Base {};
    struct D2: virtual Base {};
    

    Then there will only be one instance of Base within TopDiamond: the job of actually instantiating it is left to the top-constructor (here TopDiamond).

    Thus, the little trick you have shown is simply explained here:

    • because Usable derives virtually from Usable_lock, it’s up to its derived class to instantiate the Usable_lock part of the object
    • because Usable_lock constructor is private, only itself and Usable (friend) can access the constructor

    It’s clever, I had never thought of that. I wonder what the cost of virtual inheritance is here (extra memory / speed overhead) ?

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