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Editorial Team
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Asked: 2026-05-26T23:50:04+00:00

I found this piece of code in perl system(zip $ZIP_DEBUG -r -9 itvlib.zip $include

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I found this piece of code in perl 

system("zip $ZIP_DEBUG -r -9 itvlib.zip $include $exclude");

However I don’t understand how it is working. I mean system() is used to fire ‘system’ commands right ? So is this ‘zip’ command used here a ‘system’ command ?
But I tried firing just the following on the command prompt; 

zip $ZIP_DEBUG -r -9 itvlib.zip arg1 arg2

It didn’t work !
it gave the following error:

'zip' is not recognized as an internal or external command,
operable program or batch file.

Well this shouldn’t have happened, since the command seems to use ‘zip’ as a system command. So this makes the command ‘zip’ mysterious

Can you please help me to understand this command with all its parameters?

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1 Answer

  1. Editorial Team
    system("zip $ZIP_DEBUG -r -9 itvlib.zip $include $exclude");

    is running a program named zip (probably zip.exe) somewhere on the path. $ZIP_DEBUG, $include, and $exclude are Perl variables that are interpolated into the command line before the command is run.

    If the system call works in the Perl script, but zip -? gives the 'zip' is not recognized as an internal or external command, operable program or batch file error, then the PATH of the Perl script must be different than the PATH in your command prompt. Or, there might be a zip command in the current directory when Perl executes the system command. (In Windows, the current directory is an implicit member of your PATH.)

    To see what the PATH is for the Perl script, you can add a print "$ENV{PATH}\n"; before the system command. To see what the PATH is in your command prompt, type PATH.

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