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Home/ Questions/Q 7444619
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T11:33:08+00:00 2026-05-29T11:33:08+00:00

I found this question while i searched the usage of metaclass in python.It’s a

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I found this question while i searched the usage of metaclass in python.It’s a good question with a wonderful answer,See Here.But while i followed the example like this:

class UpperAttrMetaclass(type): 

    def __new__(cls, name, bases, dct):

        attrs = ((name, value) for name, value in dct.items() if not name.startswith('__'))
        uppercase_attr = dict((name.upper(), value) for name, value in attrs)

        return type.__new__(cls, name, bases, uppercase_attr)
class Foo(object):
    __metaclass__=UpperAttrMetaclass
    bar = 'bip'

Then:

print(hasattr(Foo,'bar'))

I was hoping it would output False,but instead it was True
It seems the metaclass didn’t change anything at all.
I must have made a mistake.Glad if you can point it out to me!

EDIT:
I was using IDLE 3.2,to make my situation more clear.

EDIT:
Thanks for all the answers.And i found a good post on this.So i post it hereMetaclass in python 2&3

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  1. Editorial Team
    Editorial Team
    2026-05-29T11:33:10+00:00Added an answer on May 29, 2026 at 11:33 am

    You made no mistake. print(hasattr(Foo,'bar')) and print dir(Foo) give me:

    False
    ['BAR', '__class__', ...
    

    What’s your Python version? Mine is 2.7.2

    If you use Python 3.x, try removing the __metaclass__ attribute and declaring your class as

    class Foo(object, metaclass=UpperAttrMetaclass):
        ...
    
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