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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:59:21+00:00 2026-05-13T05:59:21+00:00

i get a date input from the user..in this case i need to determine

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i get a date input from the user..in this case i need to determine if the year the user entered is a leap year or not …and after the user has entered the entire date i.e the month date and year…i need to check if the date is in fact valid if yes need to determine the day for that particular date.. can some one tell me how this could be done..

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:59:21+00:00Added an answer on May 13, 2026 at 5:59 am
    /* Returns true if the given year is a leap year */
    static bool IsLeapYear(int year)
    {
        if ((year % 400) == 0)
            return true;
        if ((year % 100) == 0)
            return false;
        if ((year % 4) == 0)
            return true;
        return false;
    }
    

        2.6. What day of the week was 2 August 1953?
        --------------------------------------------
    
        To calculate the day on which a particular date falls, the following
        algorithm may be used (the divisions are integer divisions, in which
        remainders are discarded):
    
        a = (14 - month) / 12
        y = year - a
        m = month + 12*a - 2
        For Julian calendar: d = (5 + day + y + y/4 + (31*m)/12) mod 7
        For Gregorian calendar: d = (day + y + y/4 - y/100 + y/400 + (31*m)/12) mod 7
    
        The value of d is 0 for a Sunday, 1 for a Monday, 2 for a Tuesday, etc.
    
        Example: On what day of the week was the author born?
    
        My birthday is 2 August 1953 (Gregorian, of course).
    
        a = (14 - 8) / 12 = 0
        y = 1953 - 0 = 1953
        m = 8 + 12*0 - 2 = 6
        d = (2 + 1953 + 1953/4 - 1953/100 + 1953/400 + (31*6)/12) mod 7
          = (2 + 1953 +  488   -    19    +     4    +    15    ) mod 7
          = 2443 mod 7
          = 0
    
        I was born on a Sunday.
    

    Read the Calendar FAQ for more information.

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