Question

I get an error stating that I got an exception before start of a result set. I’m trying to get a value (score from the MySQL database) and add one to the Java rank based on the player score. This is to create a scoreboard.

So if the player’s score is lower than the current score, it gets posted with rank 1. If it’s higher, the program checks the score against the next entry in the MySQL database. I haven’t yet implemented a feature to change all the current entries rank’s to increment by 1.

Bottom Line: I’m creating a scoreboard using MySQL and Java. The Java program creates a score entry based on input, and then sends it off to the MySQL database.

      System.out.println("Your score is: "+score*2+"  (A lower score is better.)");
      try {
   // create a java mysql database connection
   String myDriver = "com.mysql.jdbc.Driver";
   String myUrl = "jdbc:mysql://4.30.110.246:3306/apesbridge2013";
   String dbName = "apesbridge2013";
   String tbName = period + "period";
   Class.forName(myDriver);
   Connection conn = DriverManager.getConnection(myUrl, "user", CENSORED);
   next = conn.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE,ResultSet.CONCUR_READ_ONLY);
   ResultSet resultSet = next.executeQuery("SELECT * FROM " + tbName);
   int cscore = resultSet.getInt("score");
   for(int sscore = score; sscore > cscore;){
       resultSet.next();
       cscore = resultSet.getInt("score");
       rank++;
   }

   stmt = conn.createStatement();
   stmt.executeUpdate("insert into " + dbName + "." + tbName + " " + "values(" + rank + ", '" + name + "', " + score + ")");
   stmt.close();
   conn.close();
 }
 catch (Exception e)
 {
   System.err.println("Got an exception! ");
   System.err.println(e.getMessage());
 }

    }

Answer 1

Put resultSet.next(); right below your executeQuery line.