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Home/ Questions/Q 7830569
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T11:17:35+00:00 2026-06-02T11:17:35+00:00

I get an error with this istruction: dp = opendir (%APPDATA%/.); output: Couldn’t open

  • 0

I get an error with this istruction:

  dp = opendir ("%APPDATA%/.");

  output: 
  Couldn't open directory: Mo such file or directory.

but I don’t get an erro with this istruction:

dp = opendir ("C:/Users/xrobot/AppData/.");

output:
.
..
Local
LocalLow
Roaming

Why ?

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  1. Editorial Team
    Editorial Team
    2026-06-02T11:17:36+00:00Added an answer on June 2, 2026 at 11:17 am

    opendir doesn’t expand meta variables like %APPDATA%, the shell does. So such things work from the command line, but not from a program. In your program, you have to use an absolute or relative path.

    You can probably obtain the required path with getenv(),

    const char *appData = getenv("APPDATA");
    if (appData) {
        dp = opendir(appData);
    } else {
        /* die or recover */
    }
    
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