Question

I get an unhandled Exception type error for the following code, even though, as I understand it, I have handled the exception in the catch block.

class NewException extends Exception{
private String msg;
public NewException(String msg){
    this.msg = msg;
}
public String getExceptionMsg(){
    return msg;
}}
class CatchException {
public static void method () throws NewException{
    try {
        throw new NewException("New exception thrown");
    }
    catch (NewException e){
        e.printStackTrace();
        System.out.println(e.getExceptionMsg());
    }
    finally {
        System.out.println("In finally");
    }
}}
public class TestExceptions{
public static void main(String[] args){
    CatchException.method();
}}

Answer 1

Your method() declares that it throws NewException. Whatever is inside that method is irrelevant:

public static void method () throws NewException{
    //...
}}

public static void main(String[] args){
    CatchException.method();
}}

The compiler sees that you are calling CatchException.method() in main() and that you are not handling it in any way (either catching or declaring main() to throw NewException as well. Thus the error.

The compiler doesn’t care if you are actually throwing that exception or not. Have a look at ByteArrayInputStream.close() – there is no way it’ll ever throw an IOException – but you still have to handle it since it’s declared.