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Home/ Questions/Q 8080631
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T16:28:40+00:00 2026-06-05T16:28:40+00:00

I get data is undefined, i guess i can’t [‘productId’] in an array, but

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I get data is undefined, i guess i can’t [‘productId’] in an array, but i think i need this structure in the json, i tried a couple of variation but it never was, what i needed
i just want to send a json via ajax.

jQuery(':checked').each(function(i){
  data[i]['productId'] =  jQuery(this).parent().find('.productId').val();
  jQuery(this).parent().find('.attrGrp').each(function(j){
    data[i]['attrGrps'][j]['uid'] = jQuery(this).find('.active').attr('id');
    data[i]['attrGrps'][j]['amount'] = jQuery(this).parent().find('.amount').val();
  });
});
jQuery.post(newSession, {json: data.serializeArray()});

is there any better way for doing it? or how can i make it work?
help appreciated ;/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T16:28:43+00:00Added an answer on June 5, 2026 at 4:28 pm

    You need to initialize arrays and objects before using them. String indexes are only possible with objects. Try this:

    var data = [];
    jQuery(':checked').each(function(i)
    {
      data[i] = {};
      data[i].productId =  jQuery(this).parent().find('.productId').val();
      data[i].attrGrps = [];
      jQuery(this).parent().find('.attrGrp').each(function(j)
      {
        data[i].attrGrps[j] = {};
        data[i].attrGrps[j].uid = jQuery(this).find('.active').attr('id');
        data[i].attrGrps[j].amount = jQuery(this).parent().find('.amount').val();
      });
    });
    

    Alternatively you could use jQuery().serialize, post everything in the form and sort it out on the server.

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