Question

I get the error:

C2275 RHandle: illegal use of this type as an expression

…when I compile this:

int main(){
    int i,j;
    float** tree;
    tree = (float**)malloc(15 * sizeof(float*));
    for( i = 0; i < 15; i++) 
        tree[i] = (float*)malloc(2 * sizeof(float));
    for(i = 0; i < 15; i++)
        for( j = 0; j < 2; j++)
            tree[i][j] = 2;

    RHandle h = create_reprVectorsTree(tree, 8, 2); // error at this line
    // ...
}

My interface looks like this:

struct reprVectorsTree;

#ifdef __cplusplus
extern "C" {
#endif

typedef struct reprVectorsTree * RHandle;
RHandle create_reprVectorsTree(float **, int , int );
void free_reprVectorsTree(RHandle);
float*  work_decode(RHandle , int *, int);

#ifdef __cplusplus
}
#endif

I followed the example from this question.

I am compiling on Visual Studio 2008.

What is the problem?

Answer 1

Just a guess, but if this is being compiled as C89 you can’t have a variable declared in the middle of the scope like that.

int main(){
int i,j;
float** tree;
RHandle h;
tree = (float**)malloc(15 * sizeof(float*));
for( i = 0; i < 15; i++) 
    tree[i] = (float*)malloc(2 * sizeof(float));
for(i = 0; i < 15; i++)
    for( j = 0; j < 2; j++)
        tree[i][j] = 2;    
h = create_reprVectorsTree(tree, 8, 2);