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Home/ Questions/Q 7924365
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T17:43:03+00:00 2026-06-03T17:43:03+00:00

I get the following error here: Line 45: <tr> Line 46: <td width=15% valign=top>

  • 0

I get the following error here:

        Line 45:         <tr>
        Line 46:             <td width="15%" valign="top">
        Line 47:                 @{Html.RenderAction("GetMenu","RoomType");}
        Line 48:             </td>
        Line 49:             <td valign="top"


 'The model item passed into the dictionary is of type   
 'System.Collections.Generic.List`1[System.Object]', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[LicentaTest.Models.RoomType]'.

I dont know where i am wrong .this is my GetMenu method from RoomTypecontroller:

      'public ActionResult GetMenu()
        {
        DBContext.Current.Open();
        var model =RoomType.SelectAll();
        DBContext.Current.Close();
        return PartialView(model);
         }'

And here is my Get menu view:

      @model IEnumerable<LicentaTest.Models.RoomType>
      @using LicentaTest.Models
      <script type="text/javascript">
      $(function () {
      $("#categories").addClass("ui-widget");
      $("a", "#categories").button().width(200);
      });
      </script>
      <ul id="categories">
      @foreach (var tipcamera in Model) 
      { 
<li>@Html.ActionLink(tipcamera.Room_Type,"Browse","RoomType",new{RoomType=tipcamera.Room_Type},null)
       </li>


        }

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T17:43:05+00:00Added an answer on June 3, 2026 at 5:43 pm

    Actually i don’t know what your RoomType.SelectAll() do but i suppose that it return a List<object> any way try this it should work:

    var model = RoomType.SelectAll().Cast<RoomType>();
    
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