Question

I get the following error message when I try this query:

$query .= "($tid, {$_POST['type']['$i']}, 'Y', NOW())";

You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near

(18, , 'Y', NOW())' at line 1

Everything in my code works except this line. I know it has to do with $_POST array variable, but i don’t know the correct syntax.

If you need more code, I will be happy to include it.

Answer 1

Your use of single quotes around $i is wrong:

$query .= "($tid, {$_POST['type']['$i']}, 'Y', NOW())";

This will cause $i to be taken literally instead of the value of $i being used (which is what I assume you need).

This should work:

$query .= "($tid, {$_POST['type'][$i]}, 'Y', NOW())";