Question

I get this error: Parse error: syntax error, unexpected $end in /home/a1633717/public_html/members.php on line 59
When I checked the code, I couldn’t find any error. Here is the code:

<?php
session_start();
require 'database.php';
$nuser=$_SESSION['user'];
$auser=$_SESSION['admin'];

if($nuser){  
    $userfinal=$nuser;    
} elseif($auser) {    
    $userfinal=$auser;
}

if(isset($userfinal)) {
    $Members = mysql_query("SELECT user FROM characters WHERE level ='1' ORDER BY exp
    DESC") or die(mysql_error());
    $numRowsMembers = mysql_num_rows($Members);
?>

<table border="0">

<?php
for($count = 1; $count <= $numRowsMembers; $count++)
{
    $name = mysql_fetch_array($Members);
?>

<tr>

<?php
    echo '<td><a href="member_profile.php?username=' . $name['user'] . '">' . name['user'] . '</a></td>';
?>

</tr>

<?php
}
?>

</table>

The error is at the bottom, and when I looked at it I did’t see an error. How can I fix that? I changed the order of and the php but nothing. Thanks in advance

Answer 1

This usually means you forgot to close a bracket, in this case, you forgot to close the if: if(isset($userfinal)){

Just add another closure bracket where you need it (probably after the last closure bracket so:

</tr>

<?php

}

?>

</table>

<?php

} // Closure of the if

?>