Question

I get this error when trying to take an integer and prepend “b” to it, converting it into a string:

  File "program.py", line 19, in getname
    name = "b" + num
TypeError: Can't convert 'int' object to str implicitly

That’s related to this function:

num = random.randint(1,25)
name = "b" + num

Answer 1

name = 'b' + str(num)

or

name = 'b%s' % num

Note that the second approach is deprecated in 3.x.