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Home/ Questions/Q 5991129
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T23:20:34+00:00 2026-05-22T23:20:34+00:00

I get this warning and I am not sure how to fix it. The

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I get this warning and I am not sure how to fix it. The line where I get the warning is

NSInteger thescore = [[myDictionary objectForKey:@"Score"] objectAtIndex:0];

If it makes a difference, myDictionary is a NSDictionary

Edit: How is this? Btw my array is a NSMutableArray and not a NSArray

NSInteger thescore = [[myDictionary valueForKey:@"Score"] integerValue];

Edit 2: @Bavarious mentioned that I should do the following:

int thescore = [[myDictionary objectForKey:@"Score"] integerValue];
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  1. Editorial Team
    Editorial Team
    2026-05-22T23:20:35+00:00Added an answer on May 22, 2026 at 11:20 pm

    The result of call [someArray objectAtIndex:0] is an object. And NSInteger is a primitive type:

    typedef long NSInteger;
    

    (cmd + double-click on NSInteger in xcode to see the definition)

    I guess you might actually be storing NSNumber objects in your array. In this case, you could do

    NSNumber *thescore = [someArray objectAtIndex:0];
    
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