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Home/ Questions/Q 7077227
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T06:23:46+00:00 2026-05-28T06:23:46+00:00

I get this when I try to run my programm : bash: ./supermarket: Permission

  • 0

I get this when I try to run my programm :
bash: ./supermarket: Permission denied

The executable files appear as binary files with read & write permissions to user but no execute permission

This is the code of my makefile can u figure out what is wrong?

OBJS    = supermarket.o cashier.o customer.o 
SOURCE  = supermarket.c cashier.c customer.c 
HEADER  = struct.h
OUT     = supermarket cashier customer
CC  = gcc
FLAGS   = -lrt -g -c 

#LIBS   = -lm
# -g option enables debugging mode 
# -c flag generates object code for separate files
# -lm math library
# -lrt semaphores

all: supermarket cashier customer

supermarket: supermarket.c
    $(CC) $(FLAGS) supermarket.c -o supermarket 

cashier: cashier.c
    $(CC) $(FLAGS) cashier.c -o cashier 

customer: customer.c
    $(CC) $(FLAGS) customer.c -o customer

# clean house
clean:
    rm -f $(OBJS) $(OUT)
# do a bit of accounting
count:
    wc $(SOURCE) $(HEADER)
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  1. Editorial Team
    Editorial Team
    2026-05-28T06:23:46+00:00Added an answer on May 28, 2026 at 6:23 am
    FLAGS   = -lrt -g -c 
    

    Specifically, the -c flag. It stops compilation at the object stage, so your supermarket, cashier, and customer “executables” are actually object files without their usual extension.

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