Question

i got a code for calling a function until meet the condition but i am not in very advance stage so code which i got not at all clear to me. here i will submit the code i got…please some one discuss about how the code works in detail.

public static void RunToFirstMatch<T>(Func<T, bool> sentry, params Func<T>[] functions)
{
     functions.Any(f => match(f()));
}

The code is called as follows

RunToFirstMatch(v => (v >= 5), Step1, ()=>Step2(1,1), Step3, Step4, ()=>0+1);

RunToFirstMatch function take 2 argument but when this function is getting called then many argument is passing….i just do not understand about the calling of the function. please discuss thanks.

Answer 1

The second argument, params Func<T>[] functions, actually means “allow many Func<T>s to be passed as subsequent arguments, and present them in an array called functions.” This is caused by the params keyword.

Thus when you call

RunToFirstMatch(v => (v >= 5), Step1, ()=>Step2(1,1), Step3, Step4, ()=>0+1)

you get

sentry = v => (v >= 5); /* or should this be called match? */
functions = new Func<T>[]
    {
        Step1,
        ()=>Step2(1,1),
        Step3,
        Step4,
        ()=>0+1
    };