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Home/ Questions/Q 6870871
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:44:09+00:00 2026-05-27T03:44:09+00:00

I got a code something like this: try: do_something() except (urllib2.URLError, socket.timeout), er: print

  • 0

I got a code something like this:

try:
     do_something()
except (urllib2.URLError, socket.timeout), er:
     print something 
except Exception, ex:
     print "The code failed because", ex, "Please review"

Now, the problem is on executing the above code I am getting following output:

The code failed because Please review

p.s.: The ‘ex’ should return the name of the exception but its not returning anything. Any idea why?

In reference to @Yuji and @Peter, I tried this code:

try:
    try:
           print x
    except Exception, ex:
           print "ex:", ex
           raise
except Exception, er:
    print "er:", er

And the Output was:

ex: name 'x' is not defined .
er: name 'x' is not defined .

Now, why raise(er) is returning an error? And why it does not in you cases?

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:44:10+00:00Added an answer on May 27, 2026 at 3:44 am

    Not necessarily – the expectation is not entirely true. The following code prints nothing:

    try:
        raise BaseException()
    except BaseException, ex:
        print ex 
    

    But this prints “abc”:

    try:
        raise BaseException("abc")
    except BaseException, ex:
        print ex
    
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