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Home/ Questions/Q 324295
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T09:06:39+00:00 2026-05-12T09:06:39+00:00

I got a generated list of links where every link has an unique id(number)

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I got a generated list of links where every link has an unique id(number) and a class called “load”.

I would like to change a picture on the other side of the page with the same number in the id as the link I clicked. Since id on elements are unique, i added folderid[number] infront of all the images

This is what i have so far (not working). I’m not sure if this is even close to correct but it feels like it 🙂

$(function(){
    $(".load").click(function(){
        var element = $(this);
        var link_id = element.attr("id");
        alert(link_id);
        $("#folderid", link_id).attr("src", "img/folder_open.gif")
    });
});

My pictures and links looks like this in the code:

<img src="img/folder.gif" id="folderid5" class="img_folder" alt="Folder"/>
<a href="#" id="5" class="load img_id5">

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T09:06:39+00:00Added an answer on May 12, 2026 at 9:06 am

    It looks like you mean to select

    $('#folderid' + link_id).attr(...)
    
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