Question

I got a Java Servelet like
http://152.252.271.12:9999/media/servlet/RequestProcessor.do

for this I need to pass parameters in Querystring like this
http://152.252.271.12:9999/media/servlet/RequestProcessor.do?input=abc

I need to read response back.

---

I tried like this.

        request.Method = "POST";
        request.KeepAlive = false;
        request.Credentials = CredentialCache.DefaultCredentials;

            using (StreamWriter writer = new StreamWriter(request.GetRequestStream()))
            {
                writer.Write(postData);
            }

            // Read Response.

            HttpWebResponse webresponse = (HttpWebResponse)request.GetResponse();

            using (StreamReader reader = new StreamReader(webresponse.GetResponseStream(), Encoding.Default))
            {
                result = reader.ReadToEnd();
                logtxn.LogTxn(result, "SPDCL RESPONSE");
            }

            webresponse.Close();

Any help appreciated..

Answer 1

Use WebRequest & WebResponse classes. Check http://gsraj.tripod.com/dotnet/webgetpost.html for more information.