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Home/ Questions/Q 4027970
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:09:45+00:00 2026-05-20T11:09:45+00:00

I got a problem on this code. json wont allow double quote results. ex.

  • 0

I got a problem on this code. json wont allow double quote results. ex. if i have a result (A sad “Story”) json wont parse it.

$('.loader1').show();
$.ajax({
  url: "findBook.php?action=populatemyacademy&bookCatId="+parentCategoryId+"",
  cache: false,
  dataType: "json",
  success: function(data) {
    $('.loader1').hide();
    $.each(data.items, function(i,item){
        $("#myAcademy").append('<div class="nameWrapper"><input name="checkMeM" type="checkbox" value="'+item.bookId+'"/><span title="'+item.bookName+'" class="checkBoxSpan">'+item.bookName+'</span></div>');
    });
}});

Here’s how i generate json on my php script

 $sql = "SELECT academyBookId, title FROM academy_book WHERE academyBookCategoryId = $bookCatId AND academyId = $academyId";
    $qPopulateAcademy = mysql_query($sql, $dbConMain) or die(__LINE__.' '.$sql.' '.mysql_error());
    while($rPopulateAcademy = mysql_fetch_array($qPopulateAcademy)){
        $rows[] = array('bookId' => $rPopulateAcademy [0], 'bookName' => $rPopulateAcademy [1]);
    }
    $jsdecode = json_encode($rows);
    echo "{items:$jsdecode}";
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:09:46+00:00Added an answer on May 20, 2026 at 11:09 am

    The problem is the server renders it as ” in your JSON document and this won’t work work because json_encode uses “” to wrap, so you can do the following:

    $jsdecode = json_encode($rows,JSON_HEX_APOS|JSON_HEX_QUOT)
    

    which will replace the apostrophes and quotes with their hex codes.

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