Question

I got a problem when I run the below code:

function newUser($email,$pwd,$pwd2,$firstname,$surname,$isAdmin=0){
  $email = $this->verify('Email',$email,10,40);
  $pwd = $this->verify('Password',$pwd,6,20);
  $pwd2 = $this->verify('Password',$pwd2,6,20);
  $firstname = $this->strToTitle($this->verify('Name',$firstname,2,40));
  $surname = $this->strToTitle($this->verify('Title',$surname,2,40));
  if ($pwd != $pwd2)
    return -1;
    $key=md5("secure")
  $result = $this->query("INSERT INTO user (email, pw, firstname, surname, isAdmin) VALUES (".$email.", AES_ENCRYPT(".$pwd.",".$key."), ".$firstname.", ".$surname.", ".$isAdmin.")");
  if (mysql_affected_rows()>0)
    return mysql_insert_id();
  else
    return 0;
}

It always prompt “Parse error: syntax error, unexpected ‘$result’ (T_VARIABLE) in F:\xampp\htdocs\sql.php on line 76”

Any one can keep me some advise??
Many thanks!!

Answer 1

A semi-colon is missing on the line assigning the result of the query to $result, it should be:

$key = md5("secure");