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Home/ Questions/Q 8075583
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T15:02:08+00:00 2026-06-05T15:02:08+00:00

I got a problem with JavaScript. I want a script that will pop-up on

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I got a problem with JavaScript.
I want a script that will pop-up on exit whole web-site a message with question and if visitor answers “NO” web page closes and if he answers “YES” he will be redirected to another page. I found a example at http://www.pgrs.net/2008/01/30/popup-when-leaving-website/ but it seems that it doesnt work for me. I couldnt find any solution.
Pleae check my code and tell me maybe i’m doing something wrong ?
Here`s my source code.

Maybe somebody will see a problem.

 <!DOCTYPE html>
<html lang="lt">
<head>
    <meta charset="utf-8">
    <title>PUA.LT</title>
    <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
    <meta name="description" content="">
    <meta name="author" content="Perfect WEB Solutions">
    <link rel="stylesheet" href="<?php echo base_url("additional/style.css") ?>">
    <script src='<?php echo base_url("additional/prototype.js")?>' type='text/javascript' ></script>
</head>
<body>
<script type="text/javascript">


Event.observe(document.body, 'click', function(event) {
  if (Event.element(event).tagName == 'A') {
    staying_in_site = true;
  }
});

window.onunload = popup;

function popup() {
  if(staying_in_site) {
    return;
  }
  alert('I see you are leaving the site');
}
</script>

</body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T15:02:10+00:00Added an answer on June 5, 2026 at 3:02 pm

    Try this:

    window.onbeforeunload = popup;
    
    function popup() {
      return 'I see you are leaving the site';
    }
    
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