Question

I got a problem with my parser. I want to read an image-link on a webiste and this normally works fine. But today I got a link that contains special chars and the usual regex did not work.

This is how my code looks like.

Pattern t = Pattern.compile(regex.trim());

Matcher x = t.matcher(content[i].toString());
if(x.find())
{
    values[i] = x.group(1);
}

And this is the part of html, that causes trouble

<div class="open-zoomview zoomlink" itemscope="" itemtype="http://schema.org/Product"> 
<img class="zoomLink productImage" src="

http://tnm.scene7.com/is/image/TNM/template_335x300?$plus_335x300$&amp;$image=is{TNM/1098845000_prod_001}&amp;$ausverkauft=1&amp;$0prozent=1&amp;$versandkostenfrei=0" alt="Produkt Atika HB 60 Benzin-Heckenschere" title="Produkt Atika HB 60 Benzin-Heckenschere" itemprop="image" /> 
</div> 

And this is the regex I am using to get the part in the src-attribute:

<img .*src="(.*?)" .*>

I believe that it has something to do with all the special character inside the link. But I’m not sure how to escape all of them. I Already tried

Pattern.quote(content[i].toString())

But the outcome was the same: nothing found.

Answer 1

The . character usually only matches everything except new line characters. Therefore, your pattern won’t match if there are newlines in the img-tag.

Use Pattern.compile(..., Pattern.DOTALL) or prepend your pattern with (?s).

In dotall mode, the expression . matches any character, including a
line terminator. By default this expression does not match line
terminators.

http://docs.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html#DOTALL