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Home/ Questions/Q 8985665
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T21:22:32+00:00 2026-06-15T21:22:32+00:00

I got a simple javascript code : ‘test1 {0} test2 test3’.replace(‘{0}’, test$’) I expected

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I got a simple javascript code :

'test1 {0} test2 test3'.replace('{0}', "test$'")

I expected the result to be test1 test$' test2 test3. But the result is test1 test test2 test3 test2 test3

This is absolutely normal. According to the mozilla documentation : https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/replace

The $' sequence has a signification in this case.

But i want to replace {0} with test$' exactly. I don’t want the $' sequence to be replace by something else. I have tried many ways :

'test1 {0} test2 test3'.replace('{0}', "test\$\'")
'test1 {0} test2 test3'.replace('{0}', "test\\$\\'")
'test1 {0} test2 test3'.replace('{0}', "test\u0024\u0027")
'test1 {0} test2 test3'.replace('{0}', "test\$'")

But nothing works.

How can i escape the $' sequence to avoid Firefox using it ?

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  1. Editorial Team
    Editorial Team
    2026-06-15T21:22:33+00:00Added an answer on June 15, 2026 at 9:22 pm

    From the page you cited:

    $$ Inserts a “$”.

    So:

    'test1 {0} test2 test3'.replace('{0}', "test$$'")
    

    This works for me on JSFiddle.net.

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