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Home/ Questions/Q 8516121
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T05:20:02+00:00 2026-06-11T05:20:02+00:00

I got code something like that: $stmt = $pdo->prepare(‘SELECT * FROM table WHERE user

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I got code something like that:

$stmt = $pdo->prepare('SELECT * FROM table WHERE user LIKE :user');

and later I got

$stmt->bindValue(':user', '%'.$user.'%', PDO::PARAM_STR);
$stmt->execute();

And it do not work. I am pretty sure that this is correct way to do a LIKE statement with MySQL, but It not works when I enter some part of username, but when I enter full username it goes like a charm.
Any ideas why LIKE statement don’t want to do a simple regex?

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  1. Editorial Team
    Editorial Team
    2026-06-11T05:20:04+00:00Added an answer on June 11, 2026 at 5:20 am

    What I use in my own code for LIKE queries is:

    $stmt = $pdo->prepare('SELECT * FROM table WHERE user LIKE CONCAT(\'%\', :user, \'%\')');
    
    $stmt->bindValue(':user', $user, PDO::PARAM_STR);
    $stmt->execute();
    

    using the CONCAT force MySQL to generate the comparison string after the $user variable has been escaped by PDO.

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