Question

I got error message

You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near GROUP BY name HAVING COUNT(DISTINCT goodfor_when.name) = 1 .

Here is part of the query where error happen

                    ....
        WHERE 
        ( `city`.`name` = "London" ) AND 
        `goodfor_what`.`name` IN ("Beers","Wine","Food") 
        GROUP BY name 

        HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime') GROUP BY name
        HAVING COUNT(DISTINCT `goodfor_when`.`name`) = 1 ORDER BY `t`.`name`, `t`.`id`;

But works if remove line

HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime') GROUP BY name

Answer 1

You can’t have two HAVING or two GROUP BY commands in the same query, and the GROUP BY must be placed before the HAVING. So, for instance :

GROUP BY name
HAVING (COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime'))
OR COUNT(DISTINCT `goodfor_when`.`name`) = 1 
ORDER BY `t`.`name`, `t`.`id`;

And more, unless t.id is an aggregated column, you’ll have to SELECT t.id and GROUP BY t.id if you want to ORDER BY t.id