Question

i got some trouble to understand scope in OOP. What i want is that $foo->test_item() prints “teststring”…Now it just fails with:

Warning: Missing argument 1 for testing::test_item()

Thanks a lot!

<?php

class testing {
    public $vari = "teststring";
    function test_item($vari){ //$this->vari doesn't work either
        print $vari;
    }
}

$foo = new testing();
$foo->test_item();

?> 

Answer 1

test_item() should be:

function test_item() {
    print $this->vari;
}

There is no need to pass $vari as a parameter.