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Home/ Questions/Q 4025324
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:49:57+00:00 2026-05-20T10:49:57+00:00

I got the following code in PHP: <?php $json = file_get_contents(‘https://graph.facebook.com/192655950766049’); $data = json_decode($json,

  • 0

I got the following code in PHP:

<?php
$json = file_get_contents('https://graph.facebook.com/192655950766049');
$data = json_decode($json, true);
echo $data['description'];
?>

and I want the equivalent code in JQuery.
I tried to do it myself but I had no luck.
Here’s one of my many tries:

<script type="text/javascript" src="../scripts/jquery-1.4.4.min.js"></script>
<script type="text/javascript">
$.getJSON("https://graph.facebook.com/192655950766049", function(json) {
   alert("JSON Data: " + json.description);
 });
</script>

I read the explanation from http://api.jquery.com/jQuery.getJSON/, but yet I dont really understand it..

anyway, if you can help me it’ll be very nice!

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:49:58+00:00Added an answer on May 20, 2026 at 10:49 am

    You need to use jquery’s jsonp request. See this short discussion on how to interface with facebook using this. JSONP allows for XSS ignoring the same origin policy.

    Basically your code would then look similar to this:

    <script type="text/javascript" src="../scripts/jquery-1.4.4.min.js"></script>
    <script type="text/javascript">
    $.getJSON("https://graph.facebook.com/192655950766049?callback=?", function(json) {
       alert("JSON Data: " + json.description);
     });
    </script>
    
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