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Home/ Questions/Q 4171510
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T00:27:12+00:00 2026-05-21T00:27:12+00:00

I got the following implementation to get the number of arguments in a variadic

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I got the following implementation to get the number of arguments in a variadic macro (currently limited to 16 args). However, for VS2010 the output is always 1, no matter how many arguments are passed. With GCC, the output is correct, bringing me to the conclusion that I must have missed something specific for MSVC (10).

#define PP_NARGS(...) \
    _xPP_NARGS_IMPL(__VA_ARGS__,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0)

#define _xPP_NARGS_IMPL(x1,x2,x3,x4,x5,x6,x7,x8,x9,x10,x11,x12,x13,x14,x15,N,...) N

int main(){
    int i = PP_NARGS(A,V,C,X,Y,Z);

    std::cout << i;

    std::cin.get();
    return 0;
}

So, question is as the title states, any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-21T00:27:13+00:00Added an answer on May 21, 2026 at 12:27 am

    Does the following work-around help?

    #define EXPAND(x) x
    #define PP_NARGS(...) \
        EXPAND(_xPP_NARGS_IMPL(__VA_ARGS__,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1,0))
    

    I think your macro isn’t wrong in particular, but
    MSVC’s __VA_ARGS__ expansion seems to behave differently from C99.

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