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Home/ Questions/Q 6670463
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:16:19+00:00 2026-05-26T03:16:19+00:00

I guess it’s easier to explain using an example: HTML: <div class=boxset> <div class=box_header>

  • 0

I guess it’s easier to explain using an example:

HTML:

<div class="boxset">
    <div class="box_header">  
        h1  
    </div>
    <div class="box">
        This is some text for box 1.
    </div>
</div>

<div class="boxset">
    <div class="box_header">  
        h2  
    </div>
    <div class="box">
        This is some text for box 2.
    </div>
</div>

<div class="boxset">
    <div class="box_header">  
        h3  
    </div>
    <div class="box">
        This is some text for box 3.
    </div>
</div>

JS:

$('.box_header').bind("click", function() {
    $('.box').not($(this).next('.box')).animate({
        'width': 'hide'
    });
    $(this).next().animate({
        'width': 'show'
    });
});

jsFiddle:

http://jsfiddle.net/rDHMF/

Here is a simple sideways accordion menu. Now when I click on a header (h1, h2, h3), its corresponding content will show and the previously opened one will close. However, I can click again on that same header I just clicked and it will contract and expand itself.

Is it possible to temporarily unbind the click event on the header I just clicked so that the ‘active’ header will just stay put when I click on it? Then bind again when I click on another header. If yes, how?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:16:20+00:00Added an answer on May 26, 2026 at 3:16 am

    This should do:

    $('.box_header').bind("click", function() {
        $('.box').not($(this).next('.box')).animate({
            'width': 'hide'
        });
        $(this).next().animate({
            'width': 'show'
        });
    });
    

    You don’t need to un/rebind the events, just prevent the box from contracting when it’s the same

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