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Home/ Questions/Q 9226837
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T04:55:30+00:00 2026-06-18T04:55:30+00:00

I guess this is best explained by code and comments: import struct class binary_buffer(str):

  • 0

I guess this is best explained by code and comments:

import struct

class binary_buffer(str):
    def __init__(self, msg=""):
        self = msg
    def write_ubyte(self, ubyte):
        self += struct.pack("=B", ubyte)
        return len(self)

Output
>> bb = binary_buffer()
>> bb # Buffer starts out empty, as it should
''
>> bb.write_ubyte(200)
1   # We can see that we've successfully written one byte to the buffer
>> bb
''  # Huh? We just wrote something, but where has it gone?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T04:55:32+00:00Added an answer on June 18, 2026 at 4:55 am

    strs are immutable. Therefore,

    self += struct.pack("=B", ubyte)
    

    is evaluated as

    self = self + struct.pack("=B", ubyte)
    

    This assigns a new value to the name self, but self is just a name like any other. As soon as the method exits, the name (and the associated object) are forgotten.

    You want a bytearray:

    >>> bb = bytearray()
    >>> bb.append(200)
    >>> bb
    bytearray(b'\xc8')
    
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