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Home/ Questions/Q 3931994
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T23:24:28+00:00 2026-05-19T23:24:28+00:00

I guess this is something easy that I’m overlooking is a clear sign of

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I guess this is something easy that I’m overlooking is a clear sign of illiteracy, but anyway.

How is that

(Map[Sign, LessEqual[x, y]]) === LessEqual[Sign[x], Sign[y]]
-> True  

But

(Map[Sign, LessEqual[-1, -100]]) == LessEqual[Sign[-1], Sign[-100]]
-> False  
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  1. Editorial Team
    Editorial Team
    2026-05-19T23:24:28+00:00Added an answer on May 19, 2026 at 11:24 pm

    Using Trace on the lhs will help to show what has happened.

    Trace[Map[Sign, LessEqual[-1, -100]]]
    

    Out[2]= {{-1 <= -100, False}, Sign /@ False, False}

    Notice that Map has no HoldXXX attributes.

    Attributes[Map]
    

    Out[3]= {Protected}

    So the LessEqual evaluates before Map does anything. At which point you get

    Map[Sign,False]
    

    As False is an atomic expression, this just evaluates to False.

    The rhs of course evaluates to True, since Sign[-1] and Sign[-100] are both -1.

    Daniel Lichtblau
    Wolfram Research

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