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Home/ Questions/Q 8043697
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T04:59:18+00:00 2026-06-05T04:59:18+00:00

I had an asynchronous function being called like this: from multiprocessing import Process def

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I had an asynchronous function being called like this:

from multiprocessing import Process

def my_function(arg1, arg2):
    print 'Long process begins'

p = Process(target=my_function, args=(arg1, arg2,)).start()

How can I make this blocking? I need to finish the process before running the rest of the script.

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  1. Editorial Team
    Editorial Team
    2026-06-05T04:59:19+00:00Added an answer on June 5, 2026 at 4:59 am

    Use p.join()

    Block the calling thread until the process whose join() method is
    called terminates or until the optional timeout occurs.

    If timeout is None then there is no timeout.

    A process can be joined many times.

    A process cannot join itself because this would cause a deadlock. It
    is an error to attempt to join a process before it has been started.

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