Question

I had an idea to replace all the NaNs in my matrix by looping through each one and using isnan. However, I suspect this will make my code run more slowly than it should. Can someone provide a better suggestion?

Answer 1

Let’s say your matrix is:

A = 
     NaN   1       6
     3     5     NaN
     4     NaN     2

You can find the NaN elements and replace them with zero using isnan like this :

A(isnan(A)) = 0;

Then your output will be:

A =
     0     1     6
     3     5     0
     4     0     2