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Home/ Questions/Q 5933051
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:55:10+00:00 2026-05-22T14:55:10+00:00

I had my query set up the other day as so $query = SELECT

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I had my query set up the other day as so

$query = "SELECT card_id,title,description,meta_description,seo_keywords,price 
FROM cards,card_cheapest order by card_id";

As you can see, I was selecting card_id,title,description,meta_description,seo_keywords from the table cards, and price was coming from cheapest_card. They both have the card_id in common (in both tables). However, I ran into a bit of an issue. When I run the query in navicat lite, I receive an error "card_id is ambiguous". Was I doing something wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:55:11+00:00Added an answer on May 22, 2026 at 2:55 pm

    When 2 or more tables have a column that is named the same, you have to qualify the table you want the column to be from.

    i.e.:

    $query = "SELECT cards.card_id,title,description,meta_description,seo_keywords,price
    FROM cards,card_cheapest order by card_id";
    

    Furthermore, do you really want to run the query this way, without a WHERE/JOIN-clause to define how to JOIN the two tables?

    $query = "SELECT cards.card_id,title,description,meta_description,seo_keywords,price 
    FROM cards,card_cheapest WHERE cards.card_id = card_cheapest.card_id 
    ORDER BY card_id";
    
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