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Asked: 2026-05-13T06:03:15+00:00

I had never worked with the datetime module in Python 2.3, and I have

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I had never worked with the datetime module in Python 2.3, and I have a very silly problem. I need to read a date in the format 

'10-JUL-2010'

then subtract a day (I would use timedelta), and return the string 

'09-JUL-2010 00:00:00 ET'

of course, this is for hundreds of dates. While it should be trivial, I cannot find the info on how to read formatted dates in Python 2.3! Help!

Edit

I am able to retrieve the formatted date as a tuple, but it will not accept the timedelta object for subtraction! Still working on it…

** Edit **

Finally… thanks to your help I was able to solve the problem as follows:

print (datetime(*(time.strptime(date_string, format)[0:6])).strftime('%d-%b-%Y')).upper()+'00:00:00 ET'
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1 Answer

  1. Editorial Team

    You’re looking for datetime.datetime.strptime(), but the documentation is awful for that function, it’s effectively the reverse operation of datetime.datetime.strftime().

    The format string you’re looking for is: '%d-%b-%Y'

    See: http://www.python.org/doc/2.3.5/lib/node211.html and http://www.python.org/doc/2.3.5/lib/datetime-datetime.html and http://www.python.org/doc/2.3.5/lib/module-time.html

    Edit: Oh snap! There is no strptime in the datetime module in python 2.3. It’s in the time module, you’ll have to use that one instead.

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