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Home/ Questions/Q 740871
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:33:59+00:00 2026-05-14T08:33:59+00:00

I had very errorsome Exception handling with if-clauses. An exception occurs if not found

  • 0

I had very errorsome Exception handling with if-clauses. An exception occurs if not found path. An exception returns the function again. The function is recursive. Safe?

$ javac SubDirs.java 
$ java SubDirs
Give me an path.
.
Dir1
Dir2
Give me an path.
IT WON'T FIND ME, SO IT RETURNS ITSELF due to Exception caught
Give me an path.

The code of Subdirs.java looks like this:

import java.io.*;
import java.util.*;

public class SubDirs {
    private List<File> getSubdirs(File file) throws IOException {
        List<File> subdirs = Arrays.asList(file.listFiles(new FileFilter() {
                    public boolean accept(File f) {
                    return f.isDirectory();
                    }
                    }));
        subdirs = new ArrayList<File>(subdirs);

        List<File> deepSubdirs = new ArrayList<File>();
        for(File subdir : subdirs) {
            deepSubdirs.addAll(getSubdirs(subdir)); 
        }
        subdirs.addAll(deepSubdirs);
        return subdirs;
    }

    public static void search() {
        try{
            BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
            String s;
            System.out.println("Give me an path.");
            while ((s = in.readLine()) != null && s.length() != 0){
                SubDirs dirs = new SubDirs();
                List<File> subDirs = dirs.getSubdirs(new File(s));
                for ( File f : subDirs ) {
                    System.out.println(f.getName());
                }
                System.out.println("Give me an path.");
            }
        }catch(Exception e){
                    // Simple but is it safe?
            search();
        }
    }

    public static void main(String[] args) throws IOException {
        search();
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:34:00+00:00Added an answer on May 14, 2026 at 8:34 am

    Debatable. I would think this leaves a mess of useless stack frames – maybe not a concern unless you try to reuse this code on a mobile device. Regardless, I wouldn’t let it pass a code review without more convincing that there’s no better way.

    For better understandability and maintainability, get in the habit of coding what you mean: if you intend the code to loop to retry on error, then code a loop. Recursion feels slicker, but, since its not a common practice in exception handlers, it increases the surprise factor. if I were a future maintainer of this code, I’d wonder if the recursion is intentional or a bug – please leave me a comment to explain the recursion is intentional.

    I would gladly exchange a few more lines of mundane code now for better maintainability and easier troubleshooting later.

    public static void search() {
    
      boolean succeeded = false;
      int attemptsLeft = MAX_ATTEMPTS;
      while (! succeeded && (--attemptsLeft > 0)) {
    
        try{
            BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
            String s;
            System.out.println("Give me an path.");
            while ((s = in.readLine()) != null && s.length() != 0){
                SubDirs dirs = new SubDirs();
                List<File> subDirs = dirs.getSubdirs(new File(s));
                for ( File f : subDirs ) {
                    System.out.println(f.getName());
                }
                System.out.println("Give me an path.");
            }
    
            succeeded = true;
    
        }catch(Exception e){
            // ALWAYS LEAVE YOURSELF A CLUE TO WHAT HAPPENED
            // e.g. the exception caught may not be the exception you expected
            e.printStackTrace();
        }
    
      } // while not succeeded yet
    
      if (! succeeded) {
        log("Hmm ... bailing search() without succeeding");
      }
    }
    
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