Question

I have 2 chars: HIGH and LOW and I’d like to convert them to an int corresponding to HIGH + the 2 left bits from LOW.

I tried somethine like :

unsigned char high;
unsigned char low;
high = 128; // 10000000
low= 128; // 10000000
int result; (should be high 10000000 + 2 left bites of low 10 = 1000000010)
// To do
return result;

Edited for more clarity.

The solution I chosed is:

return high*4 + (low >> (CHAR_BIT - 2));

Answer 1

You declare HIGH and LOW as char*, but you don’t use them as pointer. The following code works fine (BTW, avoid upper case identifiers when you don’t use constants):

char high = 125;
char low = 12;

This is how I understand your question (it could be more understandable):

#include <limits.h>

int result = high + (low >> (CHAR_BIT - 2));