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Home/ Questions/Q 7991525
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:18:56+00:00 2026-06-04T13:18:56+00:00

I have 2 divs, #col1 and #col2 , that I need to generate some

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I have 2 divs, #col1 and #col2, that I need to generate some divs with fruit names in there.

So far I have:

var fruitArray = ['apples','banana','orange','grapes'];
for (fruit in fruitArray) {
    $('<div class="'+fruitArray[fruit]+'"></div>').appendTo('#col1').doSomething(); 

    $('<div id="'+fruitArray[fruit]+'"></div>').appendTo('#col2').doSomething(); 
}

Which turns out like:

<div id="#col1">
    <div class="apples"></div>
    <div class="banana"></div>
    <div class="orange"></div>
    <div class="grapes"></div>
</div>
<div id="#col2">
    <div id="apples"></div>
    <div id="banana"></div>
    <div id="orange"></div>
    <div id="grapes"></div>
</div>

How do I randomize the array so it looks something like:

<div id="#col1">
    <div class="orange"></div>
    <div class="apples"></div>
    <div class="orange"></div>
    <div class="grapes"></div>
</div>
<div id="#col2">
    <div id="grapes"></div>
    <div id="orange"></div>
    <div id="apples"></div>
    <div id="banana"></div>
</div>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:18:58+00:00Added an answer on June 4, 2026 at 1:18 pm

    Simple shuffle extension:

    Array.prototype.shuffle = function() {
        var shuffledArray = [];
        while (this.length) {
            shuffledArray.push(this.splice(Math.random() * this.length, 1)[0]);
        }
        while (shuffledArray.length) {
            this.push(shuffledArray.pop());
        }
        return this;
    }
    

    Use it like

    var fruitArray = ['apples','banana','orange','grapes'].shuffle();
    for (var i = 0; i < fruitArray.length; i++) {            
        $('<div class="'+fruitArray[i]+'"></div>').appendTo('#col1').doSomething(); 
    
        $('<div id="'+fruitArray[i]+'"></div>').appendTo('#col2').doSomething(); 
    }
    
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