Question

I have 2 doubles x and y. When I divide x/y I dont get the result I am hoping to get.

Here is the printf command I am using in c and the output I am getting:

command:

printf("%3.10f %3.2f %3.12f %d\n",x,y,x/y,(int)(x/y));

output:

1.0000000000 0.10 10.000000000000 9

To me, x/y ought to be 10 and so not sure why (int)(x/y) is producing 9 instead of 10.

Can someone help me understand this surce of this problem please?

Answer 1

This happens because you are truncating the decimal part. Round it, and you should be fine.

printf("%3.10f %3.2f %3.12f %d\n",x,y,x/y,round(x/y));