Question

I have 2 doubts regarding basics of pointers usage.

With the following code

 int (*p_b)[10];
 p_b = new int[3][10];
 // ..do my stuff
 delete [] p_b

p_b is pointing to an array of 3 elements, each having fixed-size length of 10 int.

Q1:

How to declare p_b if I want that each element be a pointer to a fixed array size?
Basically I want the following

  p_b[0] = pointer to a fixed-array size of 10
  p_b[1] = pointer to a fixed-array size of 10
  // ... and so on

I was thinking to int (** p_b)[10] but then I don’t know how to use new to allocate it? I would like to avoid falling back to more general int** p_b

Q2:

Is per my original code sample above, how to call new so that p_b points to a unique fixed-size array of 10 int other than calling p_b = new int[1][10] ? To free memory I have to call delete[] while I cannot find an expression where I can call only simply delete.

Answer 1

p_b is pointing to an array of 3 elements, each having fixed-size length of 10 int.

How to declare p_b if I want that each element be a pointer to a fixed array size?

Does your first sentence not completely cover that question?

Is per my original code sample above, how to call new so that p_b points to a unique fixed-size array of 10 int other than calling p_b = new int[1][10]? To free memory I have to call delete[] while I cannot find an expression where I can call only simply delete.

I completely do not understand why this is a problem, but you could do it by wrapping your array inside another type… say std::array, boost::array or std::vector.