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Home/ Questions/Q 614975
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:10:11+00:00 2026-05-13T18:10:11+00:00

I have 2 functions, the function get_user_info() which connects to a db called ‘users’,

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I have 2 functions, the function get_user_info() which connects to a db called ‘users’, and another, called print_info() which connects to a db called ‘blah’. I call get_user_info() inside print_info(), so it can retrieve the information. They connect to 2 different databases and make 2 different connections, i use another function to connect to the db which is called connect_db($dbidhere). When I call get_user_info() it like cancels out the other connection, and I have to reconnect to the db called ‘blah’ after I call get_user_info(). Is there a way to have a private connection just for inside a function and doesnt cancel out the other connection?

function get_user_info() {
connect_db($db1);
$query = 'blah blah';
$row = mysql_fetch_array($query);
echo $row['cool'];
}

function print_info() {
connect_db($db2);
$query = 'blah blah again';
get_user_info(); // Here is where it cancels out the 'connect_db($db2)' and replaces it with get_user_info connection
}
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  1. Editorial Team
    Editorial Team
    2026-05-13T18:10:11+00:00Added an answer on May 13, 2026 at 6:10 pm

    It doesn’t cancel it out, you ask it to replace the default connection.

    You probably want to take a look at how you can use the returned value from mysql_connect as an optional link identifier argument to most functions like mysql_query that talks to the database.

    Edit: Assuming that you aren’t already, it is hard to say as you have omitted both the mysql_query() and the mysql_connect() calls.

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