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Home/ Questions/Q 579631
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:23:12+00:00 2026-05-13T14:23:12+00:00

I have 2 models with a 1-1 relation (essentially a resource pool). For the

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I have 2 models with a 1-1 relation (essentially a resource pool). For the example code, I will simply use nuts and bolts. There will be many more nuts (available resources) than bolts (which will each require 1 nut). However, if a nut can only be assigned to one bolt.

The constraint is easy enough to set up with the unique=True named param to the ForeignKey method.

The problem arises from the ModelForm. When rendered, the form will contain every nut in the dropdown. I would like to restrict it to only show nuts that haven’t already been claimed by a bolt.

I am aware of the fields attribute of the ModelForm class, but am unable to come up with a query set filter that adequately addresses the issue. Here is example code of my problem:

from django.db import models
from django.forms import ModelForm

# Create your models here.

class Nut(models.Model):
    size = models.CharField()

class Bolt(models.Model):
    size = models.CharField()
    nut = models.ForeignKey( Nut, unique=True )

class BoltForm(ModelForm):
    def __init__(self, *args, **kwargs):
        super(BoltForm, self).__init__(*args, **kwargs)
        self.fields['nut'].queryset = # All unassigned nuts
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  1. Editorial Team
    Editorial Team
    2026-05-13T14:23:13+00:00Added an answer on May 13, 2026 at 2:23 pm

    Try this:

    self.fields['nut'].queryset = Nut.objects.exclude(
        pk__in=Bolt.objects.values('nut').query)
    

    Update:

    Of three expressions generating the same sql query:

    pk__in=Bolt.objects.values('nut')
    pk__in=Bolt.objects.values_list('nut')
    pk__in=Bolt.objects.values('nut').query
    

    I’d choose the last one as most straight-forward (although in other two cases the list and dict aren’t created in fact: django ‘understands’ the intention without explicit mentioning of .query)

    Also, consider Daniel Roseman’s answer. It is another approach to do the same thing.

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